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Solve for t
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t+x=tx
Variable t cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by tx, the least common multiple of x,t.
t+x-tx=0
Subtract tx from both sides.
t-tx=-x
Subtract x from both sides. Anything subtracted from zero gives its negation.
\left(1-x\right)t=-x
Combine all terms containing t.
\frac{\left(1-x\right)t}{1-x}=-\frac{x}{1-x}
Divide both sides by 1-x.
t=-\frac{x}{1-x}
Dividing by 1-x undoes the multiplication by 1-x.
t=-\frac{x}{1-x}\text{, }t\neq 0
Variable t cannot be equal to 0.
t+x=tx
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by tx, the least common multiple of x,t.
t+x-tx=0
Subtract tx from both sides.
x-tx=-t
Subtract t from both sides. Anything subtracted from zero gives its negation.
\left(1-t\right)x=-t
Combine all terms containing x.
\frac{\left(1-t\right)x}{1-t}=-\frac{t}{1-t}
Divide both sides by 1-t.
x=-\frac{t}{1-t}
Dividing by 1-t undoes the multiplication by 1-t.
x=-\frac{t}{1-t}\text{, }x\neq 0
Variable x cannot be equal to 0.