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\frac{x^{2}+9-6x}{9}
Factor out \frac{1}{9}.
\left(x-3\right)^{2}
Consider x^{2}+9-6x. Use the perfect square formula, a^{2}-2ab+b^{2}=\left(a-b\right)^{2}, where a=x and b=3.
\frac{\left(x-3\right)^{2}}{9}
Rewrite the complete factored expression.