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8x\times \frac{1}{8}+8x\times \frac{1}{8}=8\times \frac{1}{16}
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 8x, the least common multiple of 8,x.
x+8x\times \frac{1}{8}=8\times \frac{1}{16}
Cancel out 8 and 8.
x+x=8\times \frac{1}{16}
Cancel out 8 and 8.
2x=8\times \frac{1}{16}
Combine x and x to get 2x.
2x=\frac{8}{16}
Multiply 8 and \frac{1}{16} to get \frac{8}{16}.
2x=\frac{1}{2}
Reduce the fraction \frac{8}{16} to lowest terms by extracting and canceling out 8.
x=\frac{\frac{1}{2}}{2}
Divide both sides by 2.
x=\frac{1}{2\times 2}
Express \frac{\frac{1}{2}}{2} as a single fraction.
x=\frac{1}{4}
Multiply 2 and 2 to get 4.