Solve 1/8left(6^2/2--2^2/2right)

$$\frac{ 1 }{ 8 } \left( \frac{ { 6 }^{ 2 } }{ 2 } - \frac{ { -2 }^{ 2 } }{ 2 } \right)$$

Evaluate

$$2$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\frac{1}{8}\left(\frac{36}{2}-\frac{\left(-2\right)^{2}}{2}\right)$$

Divide 36 by 2 to get 18.

$$\frac{1}{8}\left(18-\frac{\left(-2\right)^{2}}{2}\right)$$

Calculate -2 to the power of 2 and get 4.

$$\frac{1}{8}\left(18-\frac{4}{2}\right)$$

Divide 4 by 2 to get 2.

$$\frac{1}{8}\left(18-2\right)$$

Subtract 2 from 18 to get 16.

$$\frac{1}{8}\times 16$$

Multiply \frac{1}{8} and 16 to get \frac{16}{8}.

$$\frac{16}{8}$$

Divide 16 by 8 to get 2.

$$2$$

Factor

$$2$$