Solve 1/6-3/42/3/2

$$\frac{ 1 }{ 6 } - \frac{ \frac{ 3 }{ 4 } \frac{ 2 }{ 3 } }{ 2 }$$

Evaluate

$$-\frac{1}{12}\approx -0.083333333$$

Solution Steps

Multiply \frac{3}{4} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{6}-\frac{\frac{3\times 2}{4\times 3}}{2}$$

Cancel out 3 in both numerator and denominator.

$$\frac{1}{6}-\frac{\frac{2}{4}}{2}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{6}-\frac{\frac{1}{2}}{2}$$

Express \frac{\frac{1}{2}}{2} as a single fraction.

$$\frac{1}{6}-\frac{1}{2\times 2}$$

Multiply 2 and 2 to get 4.

$$\frac{1}{6}-\frac{1}{4}$$

Least common multiple of 6 and 4 is 12. Convert \frac{1}{6} and \frac{1}{4} to fractions with denominator 12.

$$\frac{2}{12}-\frac{3}{12}$$

Since \frac{2}{12} and \frac{3}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-3}{12}$$

Subtract 3 from 2 to get -1.

$$-\frac{1}{12}$$

Factor

$$-\frac{1}{12} = -0.08333333333333333$$