Solve 1/69^2+1/46^2

$$\frac{ 1 }{ 6 } { 9 }^{ 2 } + \frac{ 1 }{ 4 } { 6 }^{ 2 }$$

Evaluate

$$\frac{45}{2}=22.5$$

Solution Steps

Calculate 9 to the power of 2 and get 81.

$$\frac{1}{6}\times 81+\frac{1}{4}\times 6^{2}$$

Multiply \frac{1}{6} and 81 to get \frac{81}{6}.

$$\frac{81}{6}+\frac{1}{4}\times 6^{2}$$

Reduce the fraction \frac{81}{6} to lowest terms by extracting and canceling out 3.

$$\frac{27}{2}+\frac{1}{4}\times 6^{2}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{27}{2}+\frac{1}{4}\times 36$$

Multiply \frac{1}{4} and 36 to get \frac{36}{4}.

$$\frac{27}{2}+\frac{36}{4}$$

Divide 36 by 4 to get 9.

$$\frac{27}{2}+9$$

Convert 9 to fraction \frac{18}{2}.

$$\frac{27}{2}+\frac{18}{2}$$

Since \frac{27}{2} and \frac{18}{2} have the same denominator, add them by adding their numerators.

$$\frac{27+18}{2}$$

Add 27 and 18 to get 45.

$$\frac{45}{2}$$

Factor

$$\frac{3 ^ {2} \cdot 5}{2} = 22\frac{1}{2} = 22.5$$