Solve 1/5--1/9+-5/9-02

$$\frac{ 1 }{ 5 } -- \frac{ 1 }{ 9 } +- \frac{ 5 }{ 9 } -02$$

Evaluate

$$-\frac{11}{45}\approx -0.244444444$$

Solution Steps

The opposite of -\frac{1}{9} is \frac{1}{9}.

$$\frac{1}{5}+\frac{1}{9}-\frac{5}{9}-0\times 2$$

Least common multiple of 5 and 9 is 45. Convert \frac{1}{5} and \frac{1}{9} to fractions with denominator 45.

$$\frac{9}{45}+\frac{5}{45}-\frac{5}{9}-0\times 2$$

Since \frac{9}{45} and \frac{5}{45} have the same denominator, add them by adding their numerators.

$$\frac{9+5}{45}-\frac{5}{9}-0\times 2$$

Add 9 and 5 to get 14.

$$\frac{14}{45}-\frac{5}{9}-0\times 2$$

Least common multiple of 45 and 9 is 45. Convert \frac{14}{45} and \frac{5}{9} to fractions with denominator 45.

$$\frac{14}{45}-\frac{25}{45}-0\times 2$$

Since \frac{14}{45} and \frac{25}{45} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14-25}{45}-0\times 2$$

Subtract 25 from 14 to get -11.

$$-\frac{11}{45}-0\times 2$$

Multiply 0 and 2 to get 0.

$$-\frac{11}{45}-0$$

Subtract 0 from -\frac{11}{45} to get -\frac{11}{45}.

$$-\frac{11}{45}$$

Factor

$$-\frac{11}{45} = -0.24444444444444444$$