Solve 1/5-19/3-7+32

$$\frac{ 1 }{ 5 } - \frac{ 19 }{ 3 } -7+32$$

Evaluate

$$\frac{283}{15}\approx 18.866666667$$

Solution Steps

Least common multiple of 5 and 3 is 15. Convert \frac{1}{5} and \frac{19}{3} to fractions with denominator 15.

$$\frac{3}{15}-\frac{95}{15}-7+32$$

Since \frac{3}{15} and \frac{95}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-95}{15}-7+32$$

Subtract 95 from 3 to get -92.

$$-\frac{92}{15}-7+32$$

Convert 7 to fraction \frac{105}{15}.

$$-\frac{92}{15}-\frac{105}{15}+32$$

Since -\frac{92}{15} and \frac{105}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-92-105}{15}+32$$

Subtract 105 from -92 to get -197.

$$-\frac{197}{15}+32$$

Convert 32 to fraction \frac{480}{15}.

$$-\frac{197}{15}+\frac{480}{15}$$

Since -\frac{197}{15} and \frac{480}{15} have the same denominator, add them by adding their numerators.

$$\frac{-197+480}{15}$$

Add -197 and 480 to get 283.

$$\frac{283}{15}$$

Factor

$$\frac{283}{3 \cdot 5} = 18\frac{13}{15} = 18.866666666666667$$