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\frac{8a^{7}b^{4}x+36a^{5}b^{3}x^{2}+54a^{3}b^{2}x^{3}+27abx^{4}}{40}
Factor out \frac{1}{40}.
abx\left(8a^{6}b^{3}+36a^{4}b^{2}x+54a^{2}bx^{2}+27x^{3}\right)
Consider 8a^{7}b^{4}x+36a^{5}b^{3}x^{2}+54a^{3}b^{2}x^{3}+27abx^{4}. Factor out abx.
\left(3x+2ba^{2}\right)^{3}
Consider 8a^{6}b^{3}+36a^{4}b^{2}x+54a^{2}bx^{2}+27x^{3}. Use the binomial cube formula, p^{3}+3p^{2}q+3pq^{2}+q^{3}=\left(p+q\right)^{3}, where p=3x and q=2ba^{2}.
\frac{abx\left(3x+2ba^{2}\right)^{3}}{40}
Rewrite the complete factored expression.