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\frac{1}{4}x=-1+\frac{1}{5}y
Add \frac{1}{5}y to both sides.
\frac{1}{4}x=\frac{y}{5}-1
The equation is in standard form.
\frac{\frac{1}{4}x}{\frac{1}{4}}=\frac{\frac{y}{5}-1}{\frac{1}{4}}
Multiply both sides by 4.
x=\frac{\frac{y}{5}-1}{\frac{1}{4}}
Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.
x=\frac{4y}{5}-4
Divide -1+\frac{y}{5} by \frac{1}{4} by multiplying -1+\frac{y}{5} by the reciprocal of \frac{1}{4}.
-\frac{1}{5}y=-1-\frac{1}{4}x
Subtract \frac{1}{4}x from both sides.
-\frac{1}{5}y=-\frac{x}{4}-1
The equation is in standard form.
\frac{-\frac{1}{5}y}{-\frac{1}{5}}=\frac{-\frac{x}{4}-1}{-\frac{1}{5}}
Multiply both sides by -5.
y=\frac{-\frac{x}{4}-1}{-\frac{1}{5}}
Dividing by -\frac{1}{5} undoes the multiplication by -\frac{1}{5}.
y=\frac{5x}{4}+5
Divide -1-\frac{x}{4} by -\frac{1}{5} by multiplying -1-\frac{x}{4} by the reciprocal of -\frac{1}{5}.