Solve 1/4-1-1/2+3

$$\frac{ 1 }{ 4 } -1- \frac{ 1 }{ 2 } +3$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Convert 1 to fraction \frac{4}{4}.

$$\frac{1}{4}-\frac{4}{4}-\frac{1}{2}+3$$

Since \frac{1}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-4}{4}-\frac{1}{2}+3$$

Subtract 4 from 1 to get -3.

$$-\frac{3}{4}-\frac{1}{2}+3$$

Least common multiple of 4 and 2 is 4. Convert -\frac{3}{4} and \frac{1}{2} to fractions with denominator 4.

$$-\frac{3}{4}-\frac{2}{4}+3$$

Since -\frac{3}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-2}{4}+3$$

Subtract 2 from -3 to get -5.

$$-\frac{5}{4}+3$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{5}{4}+\frac{12}{4}$$

Since -\frac{5}{4} and \frac{12}{4} have the same denominator, add them by adding their numerators.

$$\frac{-5+12}{4}$$

Add -5 and 12 to get 7.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$