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\frac{1}{4}+\frac{4}{4}+3-\frac{5}{2}=\frac{2}{3}x
Convert 1 to fraction \frac{4}{4}.
\frac{1+4}{4}+3-\frac{5}{2}=\frac{2}{3}x
Since \frac{1}{4} and \frac{4}{4} have the same denominator, add them by adding their numerators.
\frac{5}{4}+3-\frac{5}{2}=\frac{2}{3}x
Add 1 and 4 to get 5.
\frac{5}{4}+\frac{12}{4}-\frac{5}{2}=\frac{2}{3}x
Convert 3 to fraction \frac{12}{4}.
\frac{5+12}{4}-\frac{5}{2}=\frac{2}{3}x
Since \frac{5}{4} and \frac{12}{4} have the same denominator, add them by adding their numerators.
\frac{17}{4}-\frac{5}{2}=\frac{2}{3}x
Add 5 and 12 to get 17.
\frac{17}{4}-\frac{10}{4}=\frac{2}{3}x
Least common multiple of 4 and 2 is 4. Convert \frac{17}{4} and \frac{5}{2} to fractions with denominator 4.
\frac{17-10}{4}=\frac{2}{3}x
Since \frac{17}{4} and \frac{10}{4} have the same denominator, subtract them by subtracting their numerators.
\frac{7}{4}=\frac{2}{3}x
Subtract 10 from 17 to get 7.
\frac{2}{3}x=\frac{7}{4}
Swap sides so that all variable terms are on the left hand side.
x=\frac{7}{4}\times \frac{3}{2}
Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.
x=\frac{7\times 3}{4\times 2}
Multiply \frac{7}{4} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
x=\frac{21}{8}
Do the multiplications in the fraction \frac{7\times 3}{4\times 2}.