Solve 1/3700+1/3300+1/4700

$$\frac{ 1 }{ 3700 } + \frac{ 1 }{ 3300 } + \frac{ 1 }{ 4700 }$$

Evaluate

$$\frac{4511}{5738700}\approx 0.000786067$$

Solution Steps

Least common multiple of 3700 and 3300 is 122100. Convert \frac{1}{3700} and \frac{1}{3300} to fractions with denominator 122100.

$$\frac{33}{122100}+\frac{37}{122100}+\frac{1}{4700}$$

Since \frac{33}{122100} and \frac{37}{122100} have the same denominator, add them by adding their numerators.

$$\frac{33+37}{122100}+\frac{1}{4700}$$

Add 33 and 37 to get 70.

$$\frac{70}{122100}+\frac{1}{4700}$$

Reduce the fraction \frac{70}{122100} to lowest terms by extracting and canceling out 10.

$$\frac{7}{12210}+\frac{1}{4700}$$

Least common multiple of 12210 and 4700 is 5738700. Convert \frac{7}{12210} and \frac{1}{4700} to fractions with denominator 5738700.

$$\frac{3290}{5738700}+\frac{1221}{5738700}$$

Since \frac{3290}{5738700} and \frac{1221}{5738700} have the same denominator, add them by adding their numerators.

$$\frac{3290+1221}{5738700}$$

Add 3290 and 1221 to get 4511.

$$\frac{4511}{5738700}$$

Factor

$$\frac{13 \cdot 347}{2 ^ {2} \cdot 3 \cdot 5 ^ {2} \cdot 11 \cdot 37 \cdot 47} = 0.0007860665307473818$$