Solve 1/36.12+1/20

$$\frac{ 1 }{ 36.12 } + \frac{ 1 }{ 20 }$$

Evaluate

$$\frac{1403}{18060}\approx 0.077685493$$

Solution Steps

Expand \frac{1}{36.12} by multiplying both numerator and the denominator by 100.

$$\frac{100}{3612}+\frac{1}{20}$$

Reduce the fraction \frac{100}{3612} to lowest terms by extracting and canceling out 4.

$$\frac{25}{903}+\frac{1}{20}$$

Least common multiple of 903 and 20 is 18060. Convert \frac{25}{903} and \frac{1}{20} to fractions with denominator 18060.

$$\frac{500}{18060}+\frac{903}{18060}$$

Since \frac{500}{18060} and \frac{903}{18060} have the same denominator, add them by adding their numerators.

$$\frac{500+903}{18060}$$

Add 500 and 903 to get 1403.

$$\frac{1403}{18060}$$

Factor

$$\frac{23 \cdot 61}{3 \cdot 5 \cdot 7 \cdot 43 \cdot 2 ^ {2}} = 0.07768549280177187$$