Solve 1/32+1/3+1/21div1

$$\frac{ 1 }{ 32 } + \frac{ 1 }{ 3 } + \frac{ 1 }{ 21 } \div 1$$

Evaluate

$$\frac{277}{672}\approx 0.412202381$$

Solution Steps

Least common multiple of 32 and 3 is 96. Convert \frac{1}{32} and \frac{1}{3} to fractions with denominator 96.

$$\frac{3}{96}+\frac{32}{96}+\frac{\frac{1}{21}}{1}$$

Since \frac{3}{96} and \frac{32}{96} have the same denominator, add them by adding their numerators.

$$\frac{3+32}{96}+\frac{\frac{1}{21}}{1}$$

Add 3 and 32 to get 35.

$$\frac{35}{96}+\frac{\frac{1}{21}}{1}$$

Anything divided by one gives itself.

$$\frac{35}{96}+\frac{1}{21}$$

Least common multiple of 96 and 21 is 672. Convert \frac{35}{96} and \frac{1}{21} to fractions with denominator 672.

$$\frac{245}{672}+\frac{32}{672}$$

Since \frac{245}{672} and \frac{32}{672} have the same denominator, add them by adding their numerators.

$$\frac{245+32}{672}$$

Add 245 and 32 to get 277.

$$\frac{277}{672}$$

Factor

$$\frac{277}{2 ^ {5} \cdot 3 \cdot 7} = 0.41220238095238093$$