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\frac{18}{30}+\frac{1}{40}x=1
Multiply \frac{1}{30} and 18 to get \frac{18}{30}.
\frac{3}{5}+\frac{1}{40}x=1
Reduce the fraction \frac{18}{30} to lowest terms by extracting and canceling out 6.
\frac{1}{40}x=1-\frac{3}{5}
Subtract \frac{3}{5} from both sides.
\frac{1}{40}x=\frac{5}{5}-\frac{3}{5}
Convert 1 to fraction \frac{5}{5}.
\frac{1}{40}x=\frac{5-3}{5}
Since \frac{5}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{40}x=\frac{2}{5}
Subtract 3 from 5 to get 2.
x=\frac{2}{5}\times 40
Multiply both sides by 40, the reciprocal of \frac{1}{40}.
x=\frac{2\times 40}{5}
Express \frac{2}{5}\times 40 as a single fraction.
x=\frac{80}{5}
Multiply 2 and 40 to get 80.
x=16
Divide 80 by 5 to get 16.