Solve 1/3x-3/8y=1

$$\frac{ 1 }{ 3 } x- \frac{ 3 }{ 8 } y = 1$$

Solve for x

$$x=\frac{9y}{8}+3$$

Steps for Solving Linear Equation

Add \frac{3}{8}y to both sides.

$$\frac{1}{3}x=1+\frac{3}{8}y$$

The equation is in standard form.

$$\frac{1}{3}x=\frac{3y}{8}+1$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{\frac{3y}{8}+1}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{\frac{3y}{8}+1}{\frac{1}{3}}$$

Divide 1+\frac{3y}{8} by \frac{1}{3} by multiplying 1+\frac{3y}{8} by the reciprocal of \frac{1}{3}.

$$x=\frac{9y}{8}+3$$

Solve for y

$$y=\frac{8\left(x-3\right)}{9}$$

Steps for Solving Linear Equation

Subtract \frac{1}{3}x from both sides.

$$-\frac{3}{8}y=1-\frac{1}{3}x$$

The equation is in standard form.

$$-\frac{3}{8}y=-\frac{x}{3}+1$$

Divide both sides of the equation by -\frac{3}{8}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{8}y}{-\frac{3}{8}}=\frac{-\frac{x}{3}+1}{-\frac{3}{8}}$$

Dividing by -\frac{3}{8} undoes the multiplication by -\frac{3}{8}.

$$y=\frac{-\frac{x}{3}+1}{-\frac{3}{8}}$$

Divide 1-\frac{x}{3} by -\frac{3}{8} by multiplying 1-\frac{x}{3} by the reciprocal of -\frac{3}{8}.

$$y=\frac{8x}{9}-\frac{8}{3}$$