Solve 1/3+7/20+1/40

$$\frac{ 1 }{ 3 } + \frac{ 7 }{ 20 } + \frac{ 1 }{ 40 }$$

Evaluate

$$\frac{17}{24}\approx 0.708333333$$

Solution Steps

Least common multiple of 3 and 20 is 60. Convert \frac{1}{3} and \frac{7}{20} to fractions with denominator 60.

$$\frac{20}{60}+\frac{21}{60}+\frac{1}{40}$$

Since \frac{20}{60} and \frac{21}{60} have the same denominator, add them by adding their numerators.

$$\frac{20+21}{60}+\frac{1}{40}$$

Add 20 and 21 to get 41.

$$\frac{41}{60}+\frac{1}{40}$$

Least common multiple of 60 and 40 is 120. Convert \frac{41}{60} and \frac{1}{40} to fractions with denominator 120.

$$\frac{82}{120}+\frac{3}{120}$$

Since \frac{82}{120} and \frac{3}{120} have the same denominator, add them by adding their numerators.

$$\frac{82+3}{120}$$

Add 82 and 3 to get 85.

$$\frac{85}{120}$$

Reduce the fraction \frac{85}{120} to lowest terms by extracting and canceling out 5.

$$\frac{17}{24}$$

Factor

$$\frac{17}{2 ^ {3} \cdot 3} = 0.7083333333333334$$