Solve 1/32^3-1/3*-2^3

$$\frac{ 1 }{ 3 } { 2 }^{ 3 } - \frac{ 1 }{ 3 } \times - { 2 }^{ 3 }$$

Evaluate

$$\frac{16}{3}\approx 5.333333333$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{1}{3}\times 8-\frac{1}{3}\left(-2^{3}\right)$$

Multiply \frac{1}{3} and 8 to get \frac{8}{3}.

$$\frac{8}{3}-\frac{1}{3}\left(-2^{3}\right)$$

Calculate 2 to the power of 3 and get 8.

$$\frac{8}{3}-\frac{1}{3}\left(-8\right)$$

Multiply \frac{1}{3} and -8 to get \frac{-8}{3}.

$$\frac{8}{3}-\frac{-8}{3}$$

Fraction \frac{-8}{3} can be rewritten as -\frac{8}{3} by extracting the negative sign.

$$\frac{8}{3}-\left(-\frac{8}{3}\right)$$

The opposite of -\frac{8}{3} is \frac{8}{3}.

$$\frac{8}{3}+\frac{8}{3}$$

Since \frac{8}{3} and \frac{8}{3} have the same denominator, add them by adding their numerators.

$$\frac{8+8}{3}$$

Add 8 and 8 to get 16.

$$\frac{16}{3}$$

Factor

$$\frac{2 ^ {4}}{3} = 5\frac{1}{3} = 5.333333333333333$$