Solve 1/25+9x>1

$$\frac{ 1 }{ 25 } +9x > 1$$

Solve for x

$$x>\frac{8}{75}$$

Solution Steps

Subtract \frac{1}{25} from both sides.

$$9x>1-\frac{1}{25}$$

Convert 1 to fraction \frac{25}{25}.

$$9x>\frac{25}{25}-\frac{1}{25}$$

Since \frac{25}{25} and \frac{1}{25} have the same denominator, subtract them by subtracting their numerators.

$$9x>\frac{25-1}{25}$$

Subtract 1 from 25 to get 24.

$$9x>\frac{24}{25}$$

Divide both sides by 9. Since 9 is positive, the inequality direction remains the same.

$$x>\frac{\frac{24}{25}}{9}$$

Express \frac{\frac{24}{25}}{9} as a single fraction.

$$x>\frac{24}{25\times 9}$$

Multiply 25 and 9 to get 225.

$$x>\frac{24}{225}$$

Reduce the fraction \frac{24}{225} to lowest terms by extracting and canceling out 3.

$$x>\frac{8}{75}$$