Solve 1/2-2^33^2+3-left(2^2right)^4^2

$$\frac{ 1 }{ 2 } - { 2 }^{ 3 } { 3 }^{ 2 } +3- { \left( { 2 }^{ 2 } \right) }^{ } { 4 }^{ 2 }$$

Evaluate

$$-\frac{265}{2}=-132.5$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 1 to get 2.

$$\frac{1}{2}-2^{3}\times 3^{2}+3-2^{2}\times 4^{2}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{1}{2}-8\times 3^{2}+3-2^{2}\times 4^{2}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{1}{2}-8\times 9+3-2^{2}\times 4^{2}$$

Multiply 8 and 9 to get 72.

$$\frac{1}{2}-72+3-2^{2}\times 4^{2}$$

Subtract 72 from \frac{1}{2} to get -\frac{143}{2}.

$$-\frac{143}{2}+3-2^{2}\times 4^{2}$$

Add -\frac{143}{2} and 3 to get -\frac{137}{2}.

$$-\frac{137}{2}-2^{2}\times 4^{2}$$

Calculate 2 to the power of 2 and get 4.

$$-\frac{137}{2}-4\times 4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$-\frac{137}{2}-4\times 16$$

Multiply 4 and 16 to get 64.

$$-\frac{137}{2}-64$$

Subtract 64 from -\frac{137}{2} to get -\frac{265}{2}.

$$-\frac{265}{2}$$

Factor

$$-\frac{265}{2} = -132\frac{1}{2} = -132.5$$