Solve 1/2(7*7)+1=1/3(9*7)+12

$$\frac{ 1 }{ 2 } (7 \times 7)+1= \frac{ 1 }{ 3 } (9 \times 7)+12$$

Verify

Solution Steps

Multiply \frac{1}{2} and 7 to get \frac{7}{2}.

$$\frac{7}{2}\times 7+1=\frac{1}{3}\times 9\times 7+12$$

Express \frac{7}{2}\times 7 as a single fraction.

$$\frac{7\times 7}{2}+1=\frac{1}{3}\times 9\times 7+12$$

Multiply 7 and 7 to get 49.

$$\frac{49}{2}+1=\frac{1}{3}\times 9\times 7+12$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{49}{2}+\frac{2}{2}=\frac{1}{3}\times 9\times 7+12$$

Since \frac{49}{2} and \frac{2}{2} have the same denominator, add them by adding their numerators.

$$\frac{49+2}{2}=\frac{1}{3}\times 9\times 7+12$$

Add 49 and 2 to get 51.

$$\frac{51}{2}=\frac{1}{3}\times 9\times 7+12$$

Multiply \frac{1}{3} and 9 to get \frac{9}{3}.

$$\frac{51}{2}=\frac{9}{3}\times 7+12$$

Divide 9 by 3 to get 3.

$$\frac{51}{2}=3\times 7+12$$

Multiply 3 and 7 to get 21.

$$\frac{51}{2}=21+12$$

Add 21 and 12 to get 33.

$$\frac{51}{2}=33$$

Convert 33 to fraction \frac{66}{2}.

$$\frac{51}{2}=\frac{66}{2}$$

Compare \frac{51}{2} and \frac{66}{2}.

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