Solve 1/2+1/6+(1/4-1/8)=

$$\frac{ 1 }{ 2 } + \frac{ 1 }{ 6 } +( \frac{ 1 }{ 4 } - \frac{ 1 }{ 8 } )=$$

Evaluate

$$\frac{19}{24}\approx 0.791666667$$

Solution Steps

Least common multiple of 2 and 6 is 6. Convert \frac{1}{2} and \frac{1}{6} to fractions with denominator 6.

$$\frac{3}{6}+\frac{1}{6}+\frac{1}{4}-\frac{1}{8}$$

Since \frac{3}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{3+1}{6}+\frac{1}{4}-\frac{1}{8}$$

Add 3 and 1 to get 4.

$$\frac{4}{6}+\frac{1}{4}-\frac{1}{8}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\frac{2}{3}+\frac{1}{4}-\frac{1}{8}$$

Least common multiple of 3 and 4 is 12. Convert \frac{2}{3} and \frac{1}{4} to fractions with denominator 12.

$$\frac{8}{12}+\frac{3}{12}-\frac{1}{8}$$

Since \frac{8}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{8+3}{12}-\frac{1}{8}$$

Add 8 and 3 to get 11.

$$\frac{11}{12}-\frac{1}{8}$$

Least common multiple of 12 and 8 is 24. Convert \frac{11}{12} and \frac{1}{8} to fractions with denominator 24.

$$\frac{22}{24}-\frac{3}{24}$$

Since \frac{22}{24} and \frac{3}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{22-3}{24}$$

Subtract 3 from 22 to get 19.

$$\frac{19}{24}$$

Factor

$$\frac{19}{2 ^ {3} \cdot 3} = 0.7916666666666666$$