Solve 1/27^2+1/8=c

$$\frac{ 1 }{ 2 } { 7 }^{ 2 } + \frac{ 1 }{ 8 } = c$$

Solve for c

$$c = \frac{197}{8} = 24\frac{5}{8} = 24.625$$

Steps for Solving Linear Equation

Calculate 7 to the power of 2 and get 49.

$$\frac{1}{2}\times 49+\frac{1}{8}=c$$

Multiply \frac{1}{2} and 49 to get \frac{49}{2}.

$$\frac{49}{2}+\frac{1}{8}=c$$

Least common multiple of 2 and 8 is 8. Convert \frac{49}{2} and \frac{1}{8} to fractions with denominator 8.

$$\frac{196}{8}+\frac{1}{8}=c$$

Since \frac{196}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{196+1}{8}=c$$

Add 196 and 1 to get 197.

$$\frac{197}{8}=c$$

Swap sides so that all variable terms are on the left hand side.

$$c=\frac{197}{8}$$