Solve for h
h = \frac{1735}{98} = 17\frac{69}{98} \approx 17.704081633
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\frac{1}{2}\times 3481-\frac{1}{2}\times 11=98h
Calculate 59 to the power of 2 and get 3481.
\frac{3481}{2}-\frac{1}{2}\times 11=98h
Multiply \frac{1}{2} and 3481 to get \frac{3481}{2}.
\frac{3481}{2}-\frac{11}{2}=98h
Multiply \frac{1}{2} and 11 to get \frac{11}{2}.
\frac{3481-11}{2}=98h
Since \frac{3481}{2} and \frac{11}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{3470}{2}=98h
Subtract 11 from 3481 to get 3470.
1735=98h
Divide 3470 by 2 to get 1735.
98h=1735
Swap sides so that all variable terms are on the left hand side.
h=\frac{1735}{98}
Divide both sides by 98.
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