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15\left(253^{2}-x^{2}\right)=-30\times 155
Multiply \frac{1}{2} and 30 to get 15.
15\left(64009-x^{2}\right)=-30\times 155
Calculate 253 to the power of 2 and get 64009.
960135-15x^{2}=-30\times 155
Use the distributive property to multiply 15 by 64009-x^{2}.
960135-15x^{2}=-4650
Multiply -30 and 155 to get -4650.
-15x^{2}=-4650-960135
Subtract 960135 from both sides.
-15x^{2}=-964785
Subtract 960135 from -4650 to get -964785.
x^{2}=\frac{-964785}{-15}
Divide both sides by -15.
x^{2}=64319
Divide -964785 by -15 to get 64319.
x=\sqrt{64319} x=-\sqrt{64319}
Take the square root of both sides of the equation.
15\left(253^{2}-x^{2}\right)=-30\times 155
Multiply \frac{1}{2} and 30 to get 15.
15\left(64009-x^{2}\right)=-30\times 155
Calculate 253 to the power of 2 and get 64009.
960135-15x^{2}=-30\times 155
Use the distributive property to multiply 15 by 64009-x^{2}.
960135-15x^{2}=-4650
Multiply -30 and 155 to get -4650.
960135-15x^{2}+4650=0
Add 4650 to both sides.
964785-15x^{2}=0
Add 960135 and 4650 to get 964785.
-15x^{2}+964785=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-15\right)\times 964785}}{2\left(-15\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -15 for a, 0 for b, and 964785 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-15\right)\times 964785}}{2\left(-15\right)}
Square 0.
x=\frac{0±\sqrt{60\times 964785}}{2\left(-15\right)}
Multiply -4 times -15.
x=\frac{0±\sqrt{57887100}}{2\left(-15\right)}
Multiply 60 times 964785.
x=\frac{0±30\sqrt{64319}}{2\left(-15\right)}
Take the square root of 57887100.
x=\frac{0±30\sqrt{64319}}{-30}
Multiply 2 times -15.
x=-\sqrt{64319}
Now solve the equation x=\frac{0±30\sqrt{64319}}{-30} when ± is plus.
x=\sqrt{64319}
Now solve the equation x=\frac{0±30\sqrt{64319}}{-30} when ± is minus.
x=-\sqrt{64319} x=\sqrt{64319}
The equation is now solved.