Solve for y
y=3
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\frac{3}{2}\left(1+y\right)+2y=12
Multiply both sides of the equation by 6, the least common multiple of 2,3.
\frac{3}{2}+\frac{3}{2}y+2y=12
Use the distributive property to multiply \frac{3}{2} by 1+y.
\frac{3}{2}+\frac{7}{2}y=12
Combine \frac{3}{2}y and 2y to get \frac{7}{2}y.
\frac{7}{2}y=12-\frac{3}{2}
Subtract \frac{3}{2} from both sides.
\frac{7}{2}y=\frac{24}{2}-\frac{3}{2}
Convert 12 to fraction \frac{24}{2}.
\frac{7}{2}y=\frac{24-3}{2}
Since \frac{24}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{7}{2}y=\frac{21}{2}
Subtract 3 from 24 to get 21.
y=\frac{21}{2}\times \frac{2}{7}
Multiply both sides by \frac{2}{7}, the reciprocal of \frac{7}{2}.
y=\frac{21\times 2}{2\times 7}
Multiply \frac{21}{2} times \frac{2}{7} by multiplying numerator times numerator and denominator times denominator.
y=\frac{21}{7}
Cancel out 2 in both numerator and denominator.
y=3
Divide 21 by 7 to get 3.
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