Solve 1/12x+1/18(17-x)=1

$$\frac{ 1 }{ 12 } x+ \frac{ 1 }{ 18 } (17-x)=1$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{18} by 17-x.

$$\frac{1}{12}x+\frac{1}{18}\times 17+\frac{1}{18}\left(-1\right)x=1$$

Multiply \frac{1}{18} and 17 to get \frac{17}{18}.

$$\frac{1}{12}x+\frac{17}{18}+\frac{1}{18}\left(-1\right)x=1$$

Multiply \frac{1}{18} and -1 to get -\frac{1}{18}.

$$\frac{1}{12}x+\frac{17}{18}-\frac{1}{18}x=1$$

Combine \frac{1}{12}x and -\frac{1}{18}x to get \frac{1}{36}x.

$$\frac{1}{36}x+\frac{17}{18}=1$$

Subtract \frac{17}{18} from both sides.

$$\frac{1}{36}x=1-\frac{17}{18}$$

Convert 1 to fraction \frac{18}{18}.

$$\frac{1}{36}x=\frac{18}{18}-\frac{17}{18}$$

Since \frac{18}{18} and \frac{17}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{36}x=\frac{18-17}{18}$$

Subtract 17 from 18 to get 1.

$$\frac{1}{36}x=\frac{1}{18}$$

Multiply both sides by 36, the reciprocal of \frac{1}{36}.

$$x=\frac{1}{18}\times 36$$

Multiply \frac{1}{18} and 36 to get \frac{36}{18}.

$$x=\frac{36}{18}$$

Divide 36 by 18 to get 2.

$$x=2$$