Solve 1/1-3+1/2(1)-8=

$$\frac{ 1 }{ 1-3 } + \frac{ 1 }{ 2(1)-8 } =$$

Evaluate

$$-\frac{2}{3}\approx -0.666666667$$

Solution Steps

Subtract 3 from 1 to get -2.

$$\frac{1}{-2}+\frac{1}{2\times 1-8}$$

Fraction \frac{1}{-2} can be rewritten as -\frac{1}{2} by extracting the negative sign.

$$-\frac{1}{2}+\frac{1}{2\times 1-8}$$

Multiply 2 and 1 to get 2.

$$-\frac{1}{2}+\frac{1}{2-8}$$

Subtract 8 from 2 to get -6.

$$-\frac{1}{2}+\frac{1}{-6}$$

Fraction \frac{1}{-6} can be rewritten as -\frac{1}{6} by extracting the negative sign.

$$-\frac{1}{2}-\frac{1}{6}$$

Least common multiple of 2 and 6 is 6. Convert -\frac{1}{2} and \frac{1}{6} to fractions with denominator 6.

$$-\frac{3}{6}-\frac{1}{6}$$

Since -\frac{3}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-1}{6}$$

Subtract 1 from -3 to get -4.

$$\frac{-4}{6}$$

Reduce the fraction \frac{-4}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{2}{3}$$

Factor

$$-\frac{2}{3} = -0.6666666666666666$$