Solve 1/-2--2^2+2(-2)

$$\frac{ 1 }{ -2 } - { -2 }^{ 2 } +2(-2)$$

Evaluate

$$-\frac{17}{2}=-8.5$$

Solution Steps

Fraction \frac{1}{-2} can be rewritten as -\frac{1}{2} by extracting the negative sign.

$$-\frac{1}{2}-\left(-2\right)^{2}+2\left(-2\right)$$

Calculate -2 to the power of 2 and get 4.

$$-\frac{1}{2}-4+2\left(-2\right)$$

Convert 4 to fraction \frac{8}{2}.

$$-\frac{1}{2}-\frac{8}{2}+2\left(-2\right)$$

Since -\frac{1}{2} and \frac{8}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1-8}{2}+2\left(-2\right)$$

Subtract 8 from -1 to get -9.

$$-\frac{9}{2}+2\left(-2\right)$$

Multiply 2 and -2 to get -4.

$$-\frac{9}{2}-4$$

Convert 4 to fraction \frac{8}{2}.

$$-\frac{9}{2}-\frac{8}{2}$$

Since -\frac{9}{2} and \frac{8}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-9-8}{2}$$

Subtract 8 from -9 to get -17.

$$-\frac{17}{2}$$

Factor

$$-\frac{17}{2} = -8\frac{1}{2} = -8.5$$