Solve 1/{left(frac{4{8}right)}^2+10}

$$\frac{ 1 }{ { \left( \frac{ 4 }{ 8 } \right) }^{ 2 } +10 }$$

Evaluate

$$\frac{4}{41}\approx 0.097560976$$

Solution Steps

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$\frac{1}{\left(\frac{1}{2}\right)^{2}+10}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{\frac{1}{4}+10}$$

Add \frac{1}{4} and 10 to get \frac{41}{4}.

$$\frac{1}{\frac{41}{4}}$$

Divide 1 by \frac{41}{4} by multiplying 1 by the reciprocal of \frac{41}{4}.

$$1\times \frac{4}{41}$$

Multiply 1 and \frac{4}{41} to get \frac{4}{41}.

$$\frac{4}{41}$$

Factor

$$\frac{2 ^ {2}}{41} = 0.0975609756097561$$