Solve 1/{left(frac{1{8}right)}^2+10}

$$\frac{ 1 }{ { \left( \frac{ 1 }{ 8 } \right) }^{ 2 } +10 }$$

Evaluate

$$\frac{64}{641}\approx 0.099843994$$

Solution Steps

Calculate \frac{1}{8} to the power of 2 and get \frac{1}{64}.

$$\frac{1}{\frac{1}{64}+10}$$

Convert 10 to fraction \frac{640}{64}.

$$\frac{1}{\frac{1}{64}+\frac{640}{64}}$$

Since \frac{1}{64} and \frac{640}{64} have the same denominator, add them by adding their numerators.

$$\frac{1}{\frac{1+640}{64}}$$

Add 1 and 640 to get 641.

$$\frac{1}{\frac{641}{64}}$$

Divide 1 by \frac{641}{64} by multiplying 1 by the reciprocal of \frac{641}{64}.

$$1\times \frac{64}{641}$$

Multiply 1 and \frac{64}{641} to get \frac{64}{641}.

$$\frac{64}{641}$$

Factor

$$\frac{2 ^ {6}}{641} = 0.0998439937597504$$