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\frac{\sqrt{3}}{\left(\sqrt{3}\right)^{2}}-\frac{\sqrt{3}}{3}
Rationalize the denominator of \frac{1}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\sqrt{3}}{3}-\frac{\sqrt{3}}{3}
The square of \sqrt{3} is 3.
0
Combine \frac{\sqrt{3}}{3} and -\frac{\sqrt{3}}{3} to get 0.
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