Solve 1/sqrt[5]{27}=1/sqrt[5]{27}*frac{sqrt[5]{27}}{sqrt[5]{27}}=

$$\frac{ 1 }{ \sqrt[ 5 ]{ 27 } } = \frac{ 1 }{ \sqrt[ 5 ]{ 27 } } \times \frac{ \sqrt[ 5 ]{ 27 } }{ \sqrt[ 5 ]{ 27 } } =$$

Verify

Solution Steps

Divide \sqrt[5]{27} by \sqrt[5]{27} to get 1.

$$\frac{1}{\sqrt[5]{27}}=\frac{1}{\sqrt[5]{27}}\times 1$$

Express \frac{1}{\sqrt[5]{27}}\times 1 as a single fraction.

$$\frac{1}{\sqrt[5]{27}}=\frac{1}{\sqrt[5]{27}}$$

Subtract \frac{1}{\sqrt[5]{27}} from both sides.

$$\frac{1}{\sqrt[5]{27}}-\frac{1}{\sqrt[5]{27}}=0$$

Subtract \frac{1}{\sqrt[5]{27}} from \frac{1}{\sqrt[5]{27}} to get 0.

$$0=0$$

Compare 0 and 0.

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