Solve 1/frac{4{3}}-(1/6+1/4)

$$\frac{ 1 }{ \frac{ 4 }{ 3 } } -( \frac{ 1 }{ 6 } + \frac{ 1 }{ 4 } )$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

Divide 1 by \frac{4}{3} by multiplying 1 by the reciprocal of \frac{4}{3}.

$$1\times \frac{3}{4}-\left(\frac{1}{6}+\frac{1}{4}\right)$$

Multiply 1 and \frac{3}{4} to get \frac{3}{4}.

$$\frac{3}{4}-\left(\frac{1}{6}+\frac{1}{4}\right)$$

Least common multiple of 6 and 4 is 12. Convert \frac{1}{6} and \frac{1}{4} to fractions with denominator 12.

$$\frac{3}{4}-\left(\frac{2}{12}+\frac{3}{12}\right)$$

Since \frac{2}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{3}{4}-\frac{2+3}{12}$$

Add 2 and 3 to get 5.

$$\frac{3}{4}-\frac{5}{12}$$

Least common multiple of 4 and 12 is 12. Convert \frac{3}{4} and \frac{5}{12} to fractions with denominator 12.

$$\frac{9}{12}-\frac{5}{12}$$

Since \frac{9}{12} and \frac{5}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-5}{12}$$

Subtract 5 from 9 to get 4.

$$\frac{4}{12}$$

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$