Solve 1/-3/2+2/4-3/

$$\frac{ 1 }{ } - \frac{ 3 }{ 2 } + \frac{ 2 }{ 4 } - \frac{ 3 }{ }$$

Evaluate

$$-3$$

Solution Steps

Divide 1 by 1 to get 1.

$$1-\frac{3}{2}+\frac{2}{4}-\frac{3}{1}$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{2}{2}-\frac{3}{2}+\frac{2}{4}-\frac{3}{1}$$

Since \frac{2}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-3}{2}+\frac{2}{4}-\frac{3}{1}$$

Subtract 3 from 2 to get -1.

$$-\frac{1}{2}+\frac{2}{4}-\frac{3}{1}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{2}+\frac{1}{2}-\frac{3}{1}$$

Add -\frac{1}{2} and \frac{1}{2} to get 0.

$$-\frac{3}{1}$$

Anything divided by one gives itself.

$$-3$$

Factor

$$-3$$