Solve 0.5-0.3/0.03*10*10+35

$$\frac{ 0.5-0.3 }{ 0.03 \cdot 10 } \times 10+35$$

Evaluate

$$\frac{125}{3}\approx 41.666666667$$

Solution Steps

Subtract 0.3 from 0.5 to get 0.2.

$$\frac{0.2}{0.03\times 10}\times 10+35$$

Multiply 0.03 and 10 to get 0.3.

$$\frac{0.2}{0.3}\times 10+35$$

Expand \frac{0.2}{0.3} by multiplying both numerator and the denominator by 10.

$$\frac{2}{3}\times 10+35$$

Express \frac{2}{3}\times 10 as a single fraction.

$$\frac{2\times 10}{3}+35$$

Multiply 2 and 10 to get 20.

$$\frac{20}{3}+35$$

Convert 35 to fraction \frac{105}{3}.

$$\frac{20}{3}+\frac{105}{3}$$

Since \frac{20}{3} and \frac{105}{3} have the same denominator, add them by adding their numerators.

$$\frac{20+105}{3}$$

Add 20 and 105 to get 125.

$$\frac{125}{3}$$

Factor

$$\frac{5 ^ {3}}{3} = 41\frac{2}{3} = 41.666666666666664$$