Solve 0.02x/0.03+1=0*18x+0.18/0.12-1.5-3x/2

$$\frac{ 0.02x }{ 0.03 } +1 = \frac{ 0 \cdot 18x+0.18 }{ 0.12 } - \frac{ 1.5-3x }{ 2 }$$

Solve for x

$$x=0.3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$2\times \frac{0.02x}{0.03}+2=2\times \frac{0\times 18x+0.18}{0.12}-\left(1.5-3x\right)$$

Divide 0.02x by 0.03 to get \frac{2}{3}x.

$$2\times \frac{2}{3}x+2=2\times \frac{0\times 18x+0.18}{0.12}-\left(1.5-3x\right)$$

Multiply 2 and \frac{2}{3} to get \frac{4}{3}.

$$\frac{4}{3}x+2=2\times \frac{0\times 18x+0.18}{0.12}-\left(1.5-3x\right)$$

Multiply 0 and 18 to get 0.

$$\frac{4}{3}x+2=2\times \frac{0x+0.18}{0.12}-\left(1.5-3x\right)$$

Anything times zero gives zero.

$$\frac{4}{3}x+2=2\times \frac{0+0.18}{0.12}-\left(1.5-3x\right)$$

Add 0 and 0.18 to get 0.18.

$$\frac{4}{3}x+2=2\times \frac{0.18}{0.12}-\left(1.5-3x\right)$$

Expand \frac{0.18}{0.12} by multiplying both numerator and the denominator by 100.

$$\frac{4}{3}x+2=2\times \frac{18}{12}-\left(1.5-3x\right)$$

Reduce the fraction \frac{18}{12} to lowest terms by extracting and canceling out 6.

$$\frac{4}{3}x+2=2\times \frac{3}{2}-\left(1.5-3x\right)$$

Cancel out 2 and 2.

$$\frac{4}{3}x+2=3-\left(1.5-3x\right)$$

To find the opposite of 1.5-3x, find the opposite of each term.

$$\frac{4}{3}x+2=3-1.5-\left(-3x\right)$$

The opposite of -3x is 3x.

$$\frac{4}{3}x+2=3-1.5+3x$$

Subtract 1.5 from 3 to get 1.5.

$$\frac{4}{3}x+2=1.5+3x$$

Subtract 3x from both sides.

$$\frac{4}{3}x+2-3x=1.5$$

Combine \frac{4}{3}x and -3x to get -\frac{5}{3}x.

$$-\frac{5}{3}x+2=1.5$$

Subtract 2 from both sides.

$$-\frac{5}{3}x=1.5-2$$

Subtract 2 from 1.5 to get -0.5.

$$-\frac{5}{3}x=-0.5$$

Divide both sides by -\frac{5}{3}.

$$x=\frac{-0.5}{-\frac{5}{3}}$$