Solve -y+6/1=x-3/-2

$$\frac{ -y+6 }{ 1 } = \frac{ x-3 }{ -2 }$$

Solve for x

$$x=2y-9$$

Solution Steps

Multiply both sides of the equation by -2.

$$-2\left(-y+6\right)=x-3$$

Use the distributive property to multiply -2 by -y+6.

$$-2\left(-y\right)-12=x-3$$

Multiply -2 and -1 to get 2.

$$2y-12=x-3$$

Swap sides so that all variable terms are on the left hand side.

$$x-3=2y-12$$

Add 3 to both sides.

$$x=2y-12+3$$

Add -12 and 3 to get -9.

$$x=2y-9$$

Solve for y

$$y=\frac{x+9}{2}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by -2.

$$-2\left(-y+6\right)=x-3$$

Use the distributive property to multiply -2 by -y+6.

$$-2\left(-y\right)-12=x-3$$

Multiply -2 and -1 to get 2.

$$2y-12=x-3$$

Add 12 to both sides.

$$2y=x-3+12$$

Add -3 and 12 to get 9.

$$2y=x+9$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{x+9}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{x+9}{2}$$