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\frac{-7\sqrt{3}}{\left(\sqrt{3}\right)^{2}}-\sqrt{3}
Rationalize the denominator of \frac{-7}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{-7\sqrt{3}}{3}-\sqrt{3}
The square of \sqrt{3} is 3.
-\frac{10}{3}\sqrt{3}
Combine \frac{-7\sqrt{3}}{3} and -\sqrt{3} to get -\frac{10}{3}\sqrt{3}.