Solve frac{-6-sqrt{36-4-49*06}}{2-49}

$$\frac{ -6- \sqrt{ 36-4-49 \cdot 06 } }{ 2-49 }$$

Evaluate

$$\frac{2\left(2\sqrt{2}+3\right)}{47}\approx 0.248018176$$

Solution Steps

Subtract 4 from 36 to get 32.

$$\frac{-6-\sqrt{32-49\times 0\times 6}}{2-49}$$

Multiply 49 and 0 to get 0.

$$\frac{-6-\sqrt{32-0\times 6}}{2-49}$$

Multiply 0 and 6 to get 0.

$$\frac{-6-\sqrt{32-0}}{2-49}$$

Subtract 0 from 32 to get 32.

$$\frac{-6-\sqrt{32}}{2-49}$$

Factor 32=4^{2}\times 2. Rewrite the square root of the product \sqrt{4^{2}\times 2} as the product of square roots \sqrt{4^{2}}\sqrt{2}. Take the square root of 4^{2}.

$$\frac{-6-4\sqrt{2}}{2-49}$$

Subtract 49 from 2 to get -47.

$$\frac{-6-4\sqrt{2}}{-47}$$

Factor

$$\frac{2 {(2 \sqrt{2} + 3)}}{47} = 0.24801817552111446$$