Solve frac{-6+sqrt{6^2--4*1-40}}{2*1}=

$$\frac{ -6+ \sqrt{ { 6 }^{ 2 } --4 \cdot 1-40 } }{ 2 \cdot 1 } =$$

Evaluate

$$-3$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\frac{-6+\sqrt{36-\left(-4\right)-40}}{2\times 1}$$

The opposite of -4 is 4.

$$\frac{-6+\sqrt{36+4-40}}{2\times 1}$$

Add 36 and 4 to get 40.

$$\frac{-6+\sqrt{40-40}}{2\times 1}$$

Subtract 40 from 40 to get 0.

$$\frac{-6+\sqrt{0}}{2\times 1}$$

Calculate the square root of 0 and get 0.

$$\frac{-6+0}{2\times 1}$$

Add -6 and 0 to get -6.

$$\frac{-6}{2\times 1}$$

Multiply 2 and 1 to get 2.

$$\frac{-6}{2}$$

Divide -6 by 2 to get -3.

$$-3$$

Factor

$$-3$$