Solve -4x+3/5(2x-1)(1-2x)(1+2x)

$$\frac{ -4x+3 }{ 5(2x-1)(1-2x)(1+2x) }$$

Evaluate

$$\frac{3-4x}{5\left(2x-1\right)\left(1-4x^{2}\right)}$$

Short Solution Steps

Use the distributive property to multiply 5 by 2x-1.

$$\frac{-4x+3}{\left(10x-5\right)\left(1-2x\right)\left(1+2x\right)}$$

Apply the distributive property by multiplying each term of 10x-5 by each term of 1-2x.

$$\frac{-4x+3}{\left(10x-20x^{2}-5+10x\right)\left(1+2x\right)}$$

Combine 10x and 10x to get 20x.

$$\frac{-4x+3}{\left(20x-20x^{2}-5\right)\left(1+2x\right)}$$

Apply the distributive property by multiplying each term of 20x-20x^{2}-5 by each term of 1+2x.

$$\frac{-4x+3}{20x+40x^{2}-20x^{2}-40x^{3}-5-10x}$$

Combine 40x^{2} and -20x^{2} to get 20x^{2}.

$$\frac{-4x+3}{20x+20x^{2}-40x^{3}-5-10x}$$

Combine 20x and -10x to get 10x.

$$\frac{-4x+3}{10x+20x^{2}-40x^{3}-5}$$

Expand

$$-\frac{4x-3}{5\left(1-2x\right)\left(4x^{2}-1\right)}$$

Short Solution Steps

Use the distributive property to multiply 5 by 2x-1.

$$\frac{-4x+3}{\left(10x-5\right)\left(1-2x\right)\left(1+2x\right)}$$

Apply the distributive property by multiplying each term of 10x-5 by each term of 1-2x.

$$\frac{-4x+3}{\left(10x-20x^{2}-5+10x\right)\left(1+2x\right)}$$

Combine 10x and 10x to get 20x.

$$\frac{-4x+3}{\left(20x-20x^{2}-5\right)\left(1+2x\right)}$$

Apply the distributive property by multiplying each term of 20x-20x^{2}-5 by each term of 1+2x.

$$\frac{-4x+3}{20x+40x^{2}-20x^{2}-40x^{3}-5-10x}$$

Combine 40x^{2} and -20x^{2} to get 20x^{2}.

$$\frac{-4x+3}{20x+20x^{2}-40x^{3}-5-10x}$$

Combine 20x and -10x to get 10x.

$$\frac{-4x+3}{10x+20x^{2}-40x^{3}-5}$$