Solve -35xy^2/7xy

$$\frac{ -35x { y }^{ 2 } }{ 7xy }$$

Evaluate

$$-5y$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{\left(-35\right)^{1}x^{1}y^{2}}{7^{1}x^{1}y^{1}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{\left(-35\right)^{1}}{7^{1}}x^{1-1}y^{2-1}$$

Subtract 1 from 1.

$$\frac{\left(-35\right)^{1}}{7^{1}}x^{0}y^{2-1}$$

For any number a except 0, a^{0}=1.

$$\frac{\left(-35\right)^{1}}{7^{1}}y^{2-1}$$

Subtract 1 from 2.

$$\frac{\left(-35\right)^{1}}{7^{1}}y^{1}$$

Divide -35 by 7.

$$-5y$$

Differentiate w.r.t. y

$$-5$$

Steps Using Definition of a Derivative

Cancel out 7xy in both numerator and denominator.

$$\frac{\mathrm{d}}{\mathrm{d}y}(-5y)$$

The derivative of ax^{n} is nax^{n-1}.

$$-5y^{1-1}$$

Subtract 1 from 1.

$$-5y^{0}$$

For any term t except 0, t^{0}=1.

$$-5$$