Evaluate
-\frac{1}{2}+i=-0.5+i
Real Part
-\frac{1}{2} = -0.5
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\frac{\left(-2-i\right)i}{2i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(-2-i\right)i}{-2}
By definition, i^{2} is -1. Calculate the denominator.
\frac{-2i-i^{2}}{-2}
Multiply -2-i times i.
\frac{-2i-\left(-1\right)}{-2}
By definition, i^{2} is -1.
\frac{1-2i}{-2}
Do the multiplications in -2i-\left(-1\right). Reorder the terms.
-\frac{1}{2}+i
Divide 1-2i by -2 to get -\frac{1}{2}+i.
Re(\frac{\left(-2-i\right)i}{2i^{2}})
Multiply both numerator and denominator of \frac{-2-i}{2i} by imaginary unit i.
Re(\frac{\left(-2-i\right)i}{-2})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{-2i-i^{2}}{-2})
Multiply -2-i times i.
Re(\frac{-2i-\left(-1\right)}{-2})
By definition, i^{2} is -1.
Re(\frac{1-2i}{-2})
Do the multiplications in -2i-\left(-1\right). Reorder the terms.
Re(-\frac{1}{2}+i)
Divide 1-2i by -2 to get -\frac{1}{2}+i.
-\frac{1}{2}
The real part of -\frac{1}{2}+i is -\frac{1}{2}.
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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