Solve for k
k=-7
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\left(k-5\right)\left(-2\right)=\left(1-k\right)\times 3
Variable k cannot be equal to any of the values 1,5 since division by zero is not defined. Multiply both sides of the equation by \left(k-5\right)\left(k-1\right), the least common multiple of k-1,5-k.
-2k+10=\left(1-k\right)\times 3
Use the distributive property to multiply k-5 by -2.
-2k+10=3-3k
Use the distributive property to multiply 1-k by 3.
-2k+10+3k=3
Add 3k to both sides.
k+10=3
Combine -2k and 3k to get k.
k=3-10
Subtract 10 from both sides.
k=-7
Subtract 10 from 3 to get -7.
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