Solve -2/32left(x-(-2right))-2

$$\frac{ -2 }{ 3 } 2 \left( x-(-2 \right) )-2$$

Evaluate

$$\frac{-4x-14}{3}$$

Solution Steps

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$-\frac{2}{3}\times 2\left(x-\left(-2\right)\right)-2$$

Express -\frac{2}{3}\times 2 as a single fraction.

$$\frac{-2\times 2}{3}\left(x-\left(-2\right)\right)-2$$

Multiply -2 and 2 to get -4.

$$\frac{-4}{3}\left(x-\left(-2\right)\right)-2$$

Fraction \frac{-4}{3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$-\frac{4}{3}\left(x-\left(-2\right)\right)-2$$

The opposite of -2 is 2.

$$-\frac{4}{3}\left(x+2\right)-2$$

Use the distributive property to multiply -\frac{4}{3} by x+2.

$$-\frac{4}{3}x-\frac{4}{3}\times 2-2$$

Express -\frac{4}{3}\times 2 as a single fraction.

$$-\frac{4}{3}x+\frac{-4\times 2}{3}-2$$

Multiply -4 and 2 to get -8.

$$-\frac{4}{3}x+\frac{-8}{3}-2$$

Fraction \frac{-8}{3} can be rewritten as -\frac{8}{3} by extracting the negative sign.

$$-\frac{4}{3}x-\frac{8}{3}-2$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{4}{3}x-\frac{8}{3}-\frac{6}{3}$$

Since -\frac{8}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{4}{3}x+\frac{-8-6}{3}$$

Subtract 6 from -8 to get -14.

$$-\frac{4}{3}x-\frac{14}{3}$$

Expand

$$\frac{-4x-14}{3}$$

Solution Steps

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$-\frac{2}{3}\times 2\left(x-\left(-2\right)\right)-2$$

Express -\frac{2}{3}\times 2 as a single fraction.

$$\frac{-2\times 2}{3}\left(x-\left(-2\right)\right)-2$$

Multiply -2 and 2 to get -4.

$$\frac{-4}{3}\left(x-\left(-2\right)\right)-2$$

Fraction \frac{-4}{3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$-\frac{4}{3}\left(x-\left(-2\right)\right)-2$$

The opposite of -2 is 2.

$$-\frac{4}{3}\left(x+2\right)-2$$

Use the distributive property to multiply -\frac{4}{3} by x+2.

$$-\frac{4}{3}x-\frac{4}{3}\times 2-2$$

Express -\frac{4}{3}\times 2 as a single fraction.

$$-\frac{4}{3}x+\frac{-4\times 2}{3}-2$$

Multiply -4 and 2 to get -8.

$$-\frac{4}{3}x+\frac{-8}{3}-2$$

Fraction \frac{-8}{3} can be rewritten as -\frac{8}{3} by extracting the negative sign.

$$-\frac{4}{3}x-\frac{8}{3}-2$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{4}{3}x-\frac{8}{3}-\frac{6}{3}$$

Since -\frac{8}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{4}{3}x+\frac{-8-6}{3}$$

Subtract 6 from -8 to get -14.

$$-\frac{4}{3}x-\frac{14}{3}$$