Solve -17c^5d^4/-51cd^3

$$\frac{ -17 { c }^{ 5 } { d }^{ 4 } }{ -51c { d }^{ 3 } }$$

Evaluate

$$\frac{dc^{4}}{3}$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{\left(-17\right)^{1}c^{5}d^{4}}{\left(-51\right)^{1}c^{1}d^{3}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{\left(-17\right)^{1}}{\left(-51\right)^{1}}c^{5-1}d^{4-3}$$

Subtract 1 from 5.

$$\frac{\left(-17\right)^{1}}{\left(-51\right)^{1}}c^{4}d^{4-3}$$

Subtract 3 from 4.

$$\frac{\left(-17\right)^{1}}{\left(-51\right)^{1}}c^{4}d^{1}$$

Reduce the fraction \frac{-17}{-51} to lowest terms by extracting and canceling out 17.

$$\frac{1}{3}c^{4}d$$

Differentiate w.r.t. d

$$\frac{c^{4}}{3}$$