Solve -163+13(2608/181)/11

$$\frac{ -163+13( \frac{ 2608 }{ 181 } ) }{ 11 }$$

Evaluate

$$\frac{4401}{1991}\approx 2.210447012$$

Solution Steps

Express 13\times \frac{2608}{181} as a single fraction.

$$\frac{-163+\frac{13\times 2608}{181}}{11}$$

Multiply 13 and 2608 to get 33904.

$$\frac{-163+\frac{33904}{181}}{11}$$

Convert -163 to fraction -\frac{29503}{181}.

$$\frac{-\frac{29503}{181}+\frac{33904}{181}}{11}$$

Since -\frac{29503}{181} and \frac{33904}{181} have the same denominator, add them by adding their numerators.

$$\frac{\frac{-29503+33904}{181}}{11}$$

Add -29503 and 33904 to get 4401.

$$\frac{\frac{4401}{181}}{11}$$

Express \frac{\frac{4401}{181}}{11} as a single fraction.

$$\frac{4401}{181\times 11}$$

Multiply 181 and 11 to get 1991.

$$\frac{4401}{1991}$$

Factor

$$\frac{3 ^ {3} \cdot 163}{11 \cdot 181} = 2\frac{419}{1991} = 2.210447011551984$$