Solve -16/6-(17/6)

$$\frac{ -16 }{ 6 } -( \frac{ 17 }{ 6 } )$$

Evaluate

$$-\frac{11}{2}=-5.5$$

Solution Steps

Reduce the fraction \frac{-16}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{8}{3}-\frac{17}{6}$$

Least common multiple of 3 and 6 is 6. Convert -\frac{8}{3} and \frac{17}{6} to fractions with denominator 6.

$$-\frac{16}{6}-\frac{17}{6}$$

Since -\frac{16}{6} and \frac{17}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-16-17}{6}$$

Subtract 17 from -16 to get -33.

$$\frac{-33}{6}$$

Reduce the fraction \frac{-33}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{11}{2}$$

Factor

$$-\frac{11}{2} = -5\frac{1}{2} = -5.5$$